Sports
Dodgers star Yoshinobu Yamamoto loses perfect game on Mookie Betts error in 8th inning, then loses no-hitter in 9th
Jack Baer · June 13, 2026
Source: Yahoo Sports · Read on source site
Yoshinobu Yamamoto was an inning from his first MLB no-hitter, and an inning-plus from the 25th perfect game in MLB history.
>The Dodgers right-hander lost a perfect game bid against the Chicago White Sox in the eighth inning when shortstop Mookie Betts booted an easy ground ball from Chase Meidroth. Second baseman Santiago Espinal had a chance to make a play off the deflection, but couldn’t get the throw off.
That error not only ended the perfect game big, it also broke a string of 45 straight batters retired by Yamamoto going back to his last start. That is tied with former White Sox ace Mark Buehrle for the second-longest such streak in MLB history, behind only Yusmeiro Petit’s 46 straight in 2014.
>Yamamoto recovered with a Jacob Gonzalez groundout to end the eighth, at which point he was at 103 pitches and still chasing a no-hitter. That bid lasted two more pitches, as White Sox center-fielder Tristan Peters hammered a homer to right field to take away both the no-no and the shutout.
The Dodgers kept Yamamoto in the game at 105 pitches and had him get one more out on an Edgar Quero fly ball, then pulled him for Alex Vesia. He went a full three times through the White Sox order, allowing only a homer and a runner that reached on an error.
>This article will be updated with more information.